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1149240431 is a prime number
BaseRepresentation
bin100010010000000…
…0000010001101111
32222002111110111102
41010200000101233
54323201143211
6310012113315
740323245123
oct10440002157
92862443442
101149240431
1153a797389
12280a6583b
13154131431
14ac8b9583
156ad60a3b
hex4480046f

1149240431 has 2 divisors, whose sum is σ = 1149240432. Its totient is φ = 1149240430.

The previous prime is 1149240377. The next prime is 1149240437. The reversal of 1149240431 is 1340429411.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1149240431 is a prime.

It is a super-2 number, since 2×11492404312 = 2641507136490131522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1149240394 and 1149240403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1149240437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574620215 + 574620216.

It is an arithmetic number, because the mean of its divisors is an integer number (574620216).

Almost surely, 21149240431 is an apocalyptic number.

1149240431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1149240431 is an equidigital number, since it uses as much as digits as its factorization.

1149240431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

The square root of 1149240431 is about 33900.4488318370. The cubic root of 1149240431 is about 1047.4588378742.

Adding to 1149240431 its reverse (1340429411), we get a palindrome (2489669842).

The spelling of 1149240431 in words is "one billion, one hundred forty-nine million, two hundred forty thousand, four hundred thirty-one".