11501150501 has 2 divisors, whose sum is σ = 11501150502. Its totient is φ = 11501150500.

The previous prime is 11501150473. The next prime is 11501150503. The reversal of 11501150501 is 10505110511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10574008900 + 927141601 = 102830^2 + 30449^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11501150501 is a prime.

Together with 11501150503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11501150503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750575250 + 5750575251.

It is an arithmetic number, because the mean of its divisors is an integer number (5750575251).

Almost surely, 2^11501150501 is an apocalyptic number.

It is an amenable number.

11501150501 is a deficient number, since it is larger than the sum of its proper divisors (1).

11501150501 is an equidigital number, since it uses as much as digits as its factorization.

11501150501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 125, while the sum is 20.

The spelling of 11501150501 in words is "eleven billion, five hundred one million, one hundred fifty thousand, five hundred one".