Base | Representation |
---|---|
bin | 11010001001101001101111… |
… | …100001001100001101011111 |
3 | 120002020002101020110002221212 |
4 | 122021221233201030031133 |
5 | 110033331102314132111 |
6 | 1044340003202415035 |
7 | 33140244045111062 |
oct | 3211515741141537 |
9 | 502202336402855 |
10 | 115012505224031 |
11 | 33712590913648 |
12 | 10a9623b36147b |
13 | 4c2382c09106c |
14 | 20588c645a8d9 |
15 | d46b14c0098b |
hex | 689a6f84c35f |
115012505224031 has 2 divisors, whose sum is σ = 115012505224032. Its totient is φ = 115012505224030.
The previous prime is 115012505224013. The next prime is 115012505224079. The reversal of 115012505224031 is 130422505210511.
Together with previous prime (115012505224013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115012505224031 - 226 = 115012438115167 is a prime.
It is a super-2 number, since 2×1150125052240312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115012505224531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57506252612015 + 57506252612016.
It is an arithmetic number, because the mean of its divisors is an integer number (57506252612016).
Almost surely, 2115012505224031 is an apocalyptic number.
115012505224031 is a deficient number, since it is larger than the sum of its proper divisors (1).
115012505224031 is an equidigital number, since it uses as much as digits as its factorization.
115012505224031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 32.
The spelling of 115012505224031 in words is "one hundred fifteen trillion, twelve billion, five hundred five million, two hundred twenty-four thousand, thirty-one".
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