1150125943 has 2 divisors, whose sum is σ = 1150125944. Its totient is φ = 1150125942.

The previous prime is 1150125941. The next prime is 1150125961. The reversal of 1150125943 is 3495210511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1150125943 - 2¹ = 1150125941 is a prime.

Together with 1150125941, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1150125941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575062971 + 575062972.

It is an arithmetic number, because the mean of its divisors is an integer number (575062972).

Almost surely, 2^1150125943 is an apocalyptic number.

1150125943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150125943 is an equidigital number, since it uses as much as digits as its factorization.

1150125943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 31.

The square root of 1150125943 is about 33913.5067930168. The cubic root of 1150125943 is about 1047.7277979104.

The spelling of 1150125943 in words is "one billion, one hundred fifty million, one hundred twenty-five thousand, nine hundred forty-three".