Base | Representation |
---|---|
bin | 10000101111001001000… |
… | …101110001111001001101 |
3 | 11001221200112111210200021 |
4 | 100233021011301321031 |
5 | 122320431240103113 |
6 | 2240210141302141 |
7 | 146044202504230 |
oct | 20571105617115 |
9 | 4057615453607 |
10 | 1150130003533 |
11 | 403849448685 |
12 | 166aa0264951 |
13 | 845c2765264 |
14 | 3d949199417 |
15 | 1edb697548d |
hex | 10bc9171e4d |
1150130003533 has 16 divisors (see below), whose sum is σ = 1342501286400. Its totient is φ = 964778605056.
The previous prime is 1150130003527. The next prime is 1150130003549. The reversal of 1150130003533 is 3353000310511.
It is not a de Polignac number, because 1150130003533 - 213 = 1150129995341 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1150130003498 and 1150130003507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1150130003573) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4531485 + ... + 4778557.
It is an arithmetic number, because the mean of its divisors is an integer number (83906330400).
Almost surely, 21150130003533 is an apocalyptic number.
It is an amenable number.
1150130003533 is a deficient number, since it is larger than the sum of its proper divisors (192371282867).
1150130003533 is a wasteful number, since it uses less digits than its factorization.
1150130003533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 261276.
The product of its (nonzero) digits is 2025, while the sum is 25.
The spelling of 1150130003533 in words is "one trillion, one hundred fifty billion, one hundred thirty million, three thousand, five hundred thirty-three".
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