115015121437 has 2 divisors, whose sum is σ = 115015121438. Its totient is φ = 115015121436.

The previous prime is 115015121413. The next prime is 115015121467. The reversal of 115015121437 is 734121510511.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104557809316 + 10457312121 = 323354^2 + 102261^2 .

It is an emirp because it is prime and its reverse (734121510511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115015121437 - 2¹⁹ = 115014597149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115015121399 and 115015121408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115015121467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57507560718 + 57507560719.

It is an arithmetic number, because the mean of its divisors is an integer number (57507560719).

Almost surely, 2^115015121437 is an apocalyptic number.

It is an amenable number.

115015121437 is a deficient number, since it is larger than the sum of its proper divisors (1).

115015121437 is an equidigital number, since it uses as much as digits as its factorization.

115015121437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4200, while the sum is 31.

Adding to 115015121437 its reverse (734121510511), we get a palindrome (849136631948).

The spelling of 115015121437 in words is "one hundred fifteen billion, fifteen million, one hundred twenty-one thousand, four hundred thirty-seven".