1150254114413 has 2 divisors, whose sum is σ = 1150254114414. Its totient is φ = 1150254114412.

The previous prime is 1150254114403. The next prime is 1150254114479. The reversal of 1150254114413 is 3144114520511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 616393001449 + 533861112964 = 785107^2 + 730658^2 .

It is an emirp because it is prime and its reverse (3144114520511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1150254114413 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1150254114413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1150254114403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575127057206 + 575127057207.

It is an arithmetic number, because the mean of its divisors is an integer number (575127057207).

Almost surely, 2^{1150254114413} is an apocalyptic number.

It is an amenable number.

1150254114413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150254114413 is an equidigital number, since it uses as much as digits as its factorization.

1150254114413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 32.

Adding to 1150254114413 its reverse (3144114520511), we get a palindrome (4294368634924).

The spelling of 1150254114413 in words is "one trillion, one hundred fifty billion, two hundred fifty-four million, one hundred fourteen thousand, four hundred thirteen".