115042003 has 2 divisors, whose sum is σ = 115042004. Its totient is φ = 115042002.

The previous prime is 115042001. The next prime is 115042019. The reversal of 115042003 is 300240511.

It is an a-pointer prime, because the next prime (115042019) can be obtained adding 115042003 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115042003 - 2¹ = 115042001 is a prime.

Together with 115042001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (115042001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57521001 + 57521002.

It is an arithmetic number, because the mean of its divisors is an integer number (57521002).

Almost surely, 2^115042003 is an apocalyptic number.

115042003 is a deficient number, since it is larger than the sum of its proper divisors (1).

115042003 is an equidigital number, since it uses as much as digits as its factorization.

115042003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 115042003 is about 10725.7635159461. The cubic root of 115042003 is about 486.3536111904.

Adding to 115042003 its reverse (300240511), we get a palindrome (415282514).

The spelling of 115042003 in words is "one hundred fifteen million, forty-two thousand, three".