Base | Representation |
---|---|
bin | 10101011011011110… |
… | …10101000001101010 |
3 | 1002200210022101110011 |
4 | 22231233111001222 |
5 | 142030212043400 |
6 | 5141335442134 |
7 | 555046120345 |
oct | 125557250152 |
9 | 32623271404 |
10 | 11504799850 |
11 | 4974183455 |
12 | 2290b2634a |
13 | 11146a039b |
14 | 7b1d5545c |
15 | 4750548ba |
hex | 2adbd506a |
11504799850 has 24 divisors (see below), whose sum is σ = 21403505088. Its totient is φ = 4600935600.
The previous prime is 11504799833. The next prime is 11504799851. The reversal of 11504799850 is 5899740511.
It is a hoax number, since the sum of its digits (49) coincides with the sum of the digits of its distinct prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 11504799794 and 11504799803.
It is not an unprimeable number, because it can be changed into a prime (11504799851) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 239557 + ... + 283543.
It is an arithmetic number, because the mean of its divisors is an integer number (891812712).
Almost surely, 211504799850 is an apocalyptic number.
11504799850 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11504799850 is a deficient number, since it is larger than the sum of its proper divisors (9898705238).
11504799850 is a wasteful number, since it uses less digits than its factorization.
11504799850 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49230 (or 49225 counting only the distinct ones).
The product of its (nonzero) digits is 453600, while the sum is 49.
The spelling of 11504799850 in words is "eleven billion, five hundred four million, seven hundred ninety-nine thousand, eight hundred fifty".
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