Base | Representation |
---|---|
bin | 110101100100110111… |
… | …0000110000000010011 |
3 | 101222222021101000010021 |
4 | 1223021232012000103 |
5 | 3341112141001311 |
6 | 124504350444311 |
7 | 11212063134355 |
oct | 1531156060023 |
9 | 358867330107 |
10 | 115053453331 |
11 | 44880747423 |
12 | 1a36b203697 |
13 | ab0745298b |
14 | 57d63db0d5 |
15 | 2ed5aac171 |
hex | 1ac9b86013 |
115053453331 has 2 divisors, whose sum is σ = 115053453332. Its totient is φ = 115053453330.
The previous prime is 115053453313. The next prime is 115053453337. The reversal of 115053453331 is 133354350511.
It is a happy number.
Together with previous prime (115053453313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115053453331 - 211 = 115053451283 is a prime.
It is a super-2 number, since 2×1150534533312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115053453337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57526726665 + 57526726666.
It is an arithmetic number, because the mean of its divisors is an integer number (57526726666).
Almost surely, 2115053453331 is an apocalyptic number.
115053453331 is a deficient number, since it is larger than the sum of its proper divisors (1).
115053453331 is an equidigital number, since it uses as much as digits as its factorization.
115053453331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
The spelling of 115053453331 in words is "one hundred fifteen billion, fifty-three million, four hundred fifty-three thousand, three hundred thirty-one".
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