115104344231 has 2 divisors, whose sum is σ = 115104344232. Its totient is φ = 115104344230.

The previous prime is 115104344221. The next prime is 115104344233. The reversal of 115104344231 is 132443401511.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115104344231 is a prime.

It is a super-2 number, since 2×115104344231² (a number of 23 digits) contains 22 as substring.

Together with 115104344233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115104344194 and 115104344203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115104344233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57552172115 + 57552172116.

It is an arithmetic number, because the mean of its divisors is an integer number (57552172116).

Almost surely, 2^115104344231 is an apocalyptic number.

115104344231 is a deficient number, since it is larger than the sum of its proper divisors (1).

115104344231 is an equidigital number, since it uses as much as digits as its factorization.

115104344231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 115104344231 its reverse (132443401511), we get a palindrome (247547745742).

The spelling of 115104344231 in words is "one hundred fifteen billion, one hundred four million, three hundred forty-four thousand, two hundred thirty-one".