11513001010 has 64 divisors (see below), whose sum is σ = 24037171200. Its totient is φ = 3888660672.

The previous prime is 11513001007. The next prime is 11513001011. The reversal of 11513001010 is 1010031511.

11513001010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×11513001010² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11513001011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2779521 + ... + 2783659.

It is an arithmetic number, because the mean of its divisors is an integer number (375580800).

Almost surely, 2^11513001010 is an apocalyptic number.

11513001010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11513001010 is an abundant number, since it is smaller than the sum of its proper divisors (12524170190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11513001010 is a wasteful number, since it uses less digits than its factorization.

11513001010 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4735.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 11513001010 its reverse (1010031511), we get a palindrome (12523032521).

The spelling of 11513001010 in words is "eleven billion, five hundred thirteen million, one thousand, ten".