Base | Representation |
---|---|
bin | 10101011100011101… |
… | …00111100000101011 |
3 | 1002201100202002201111 |
4 | 22232032213200223 |
5 | 142034312031102 |
6 | 5142231331151 |
7 | 555205621402 |
oct | 125616474053 |
9 | 32640662644 |
10 | 11513002027 |
11 | 497887590a |
12 | 2293820ab7 |
13 | 11162b2847 |
14 | 7b308c639 |
15 | 475b24cd7 |
hex | 2ae3a782b |
11513002027 has 2 divisors, whose sum is σ = 11513002028. Its totient is φ = 11513002026.
The previous prime is 11513001959. The next prime is 11513002049. The reversal of 11513002027 is 72020031511.
It is a happy number.
It is an a-pointer prime, because the next prime (11513002049) can be obtained adding 11513002027 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11513002027 is a prime.
It is a super-2 number, since 2×115130020272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11513001989 and 11513002007.
It is not a weakly prime, because it can be changed into another prime (11513002087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756501013 + 5756501014.
It is an arithmetic number, because the mean of its divisors is an integer number (5756501014).
Almost surely, 211513002027 is an apocalyptic number.
11513002027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513002027 is an equidigital number, since it uses as much as digits as its factorization.
11513002027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 22.
Adding to 11513002027 its reverse (72020031511), we get a palindrome (83533033538).
The spelling of 11513002027 in words is "eleven billion, five hundred thirteen million, two thousand, twenty-seven".
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