Base | Representation |
---|---|
bin | 10101011100011101… |
… | …01101001001011111 |
3 | 1002201100210021101202 |
4 | 22232032231021133 |
5 | 142034313300434 |
6 | 5142232030115 |
7 | 555206045621 |
oct | 125616551137 |
9 | 32640707352 |
10 | 11513025119 |
11 | 49788911a2 |
12 | 229383233b |
13 | 11162c01cb |
14 | 7b3096c11 |
15 | 475b2ba7e |
hex | 2ae3ad25f |
11513025119 has 2 divisors, whose sum is σ = 11513025120. Its totient is φ = 11513025118.
The previous prime is 11513025109. The next prime is 11513025169. The reversal of 11513025119 is 91152031511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11513025119 - 220 = 11511976543 is a prime.
It is a super-2 number, since 2×115130251192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11513025091 and 11513025100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11513025109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756512559 + 5756512560.
It is an arithmetic number, because the mean of its divisors is an integer number (5756512560).
Almost surely, 211513025119 is an apocalyptic number.
11513025119 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513025119 is an equidigital number, since it uses as much as digits as its factorization.
11513025119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 29.
The spelling of 11513025119 in words is "eleven billion, five hundred thirteen million, twenty-five thousand, one hundred nineteen".
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