Base | Representation |
---|---|
bin | 10101011100011101… |
… | …01101001010010001 |
3 | 1002201100210021110121 |
4 | 22232032231022101 |
5 | 142034313301134 |
6 | 5142232030241 |
7 | 555206046022 |
oct | 125616551221 |
9 | 32640707417 |
10 | 11513025169 |
11 | 4978891238 |
12 | 2293832381 |
13 | 11162c0239 |
14 | 7b3096c49 |
15 | 475b2bab4 |
hex | 2ae3ad291 |
11513025169 has 2 divisors, whose sum is σ = 11513025170. Its totient is φ = 11513025168.
The previous prime is 11513025119. The next prime is 11513025211. The reversal of 11513025169 is 96152031511.
11513025169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7529900625 + 3983124544 = 86775^2 + 63112^2 .
It is a cyclic number.
It is not a de Polignac number, because 11513025169 - 217 = 11512894097 is a prime.
It is a super-2 number, since 2×115130251692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11513025109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756512584 + 5756512585.
It is an arithmetic number, because the mean of its divisors is an integer number (5756512585).
Almost surely, 211513025169 is an apocalyptic number.
It is an amenable number.
11513025169 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513025169 is an equidigital number, since it uses as much as digits as its factorization.
11513025169 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 34.
The spelling of 11513025169 in words is "eleven billion, five hundred thirteen million, twenty-five thousand, one hundred sixty-nine".
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