Base | Representation |
---|---|
bin | 10101011100011111… |
… | …00010011101010111 |
3 | 1002201101012100221011 |
4 | 22232033202131113 |
5 | 142034342242404 |
6 | 5142240433051 |
7 | 555210645343 |
oct | 125617423527 |
9 | 32641170834 |
10 | 11513243479 |
11 | 4978a20261 |
12 | 2293918787 |
13 | 111636870a |
14 | 7b3112623 |
15 | 475b71604 |
hex | 2ae3e2757 |
11513243479 has 2 divisors, whose sum is σ = 11513243480. Its totient is φ = 11513243478.
The previous prime is 11513243473. The next prime is 11513243519. The reversal of 11513243479 is 97434231511.
It is an a-pointer prime, because the next prime (11513243519) can be obtained adding 11513243479 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11513243479 - 25 = 11513243447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11513243473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756621739 + 5756621740.
It is an arithmetic number, because the mean of its divisors is an integer number (5756621740).
Almost surely, 211513243479 is an apocalyptic number.
11513243479 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513243479 is an equidigital number, since it uses as much as digits as its factorization.
11513243479 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90720, while the sum is 40.
The spelling of 11513243479 in words is "eleven billion, five hundred thirteen million, two hundred forty-three thousand, four hundred seventy-nine".
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