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115133450323 is a prime number
BaseRepresentation
bin110101100111001111…
…1010000100001010011
3102000011211220021100211
41223032133100201103
53341243130402243
6124520325224551
711214054115633
oct1531637204123
9360154807324
10115133450323
1144911916341
121a391b62157
13ab1abb1888
145802ca26c3
152edcb0ed9d
hex1ace7d0853

115133450323 has 2 divisors, whose sum is σ = 115133450324. Its totient is φ = 115133450322.

The previous prime is 115133450321. The next prime is 115133450437. The reversal of 115133450323 is 323054331511.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (323054331511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115133450323 - 21 = 115133450321 is a prime.

It is a super-2 number, since 2×1151334503232 (a number of 23 digits) contains 22 as substring.

Together with 115133450321, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (115133450321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57566725161 + 57566725162.

It is an arithmetic number, because the mean of its divisors is an integer number (57566725162).

Almost surely, 2115133450323 is an apocalyptic number.

115133450323 is a deficient number, since it is larger than the sum of its proper divisors (1).

115133450323 is an equidigital number, since it uses as much as digits as its factorization.

115133450323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 115133450323 its reverse (323054331511), we get a palindrome (438187781834).

The spelling of 115133450323 in words is "one hundred fifteen billion, one hundred thirty-three million, four hundred fifty thousand, three hundred twenty-three".