Base | Representation |
---|---|
bin | 1010011110001111011110… |
… | …0110000110011011001111 |
3 | 1111202210100220010022022101 |
4 | 2213203313212012123033 |
5 | 3002124014034012143 |
6 | 40253433100455531 |
7 | 2265623110521160 |
oct | 247436746063317 |
9 | 44683326108271 |
10 | 11514666313423 |
11 | 373a384a46799 |
12 | 135b75254a5a7 |
13 | 656a9cc270a0 |
14 | 2bb45455b767 |
15 | 14e7c9b8bb4d |
hex | a78f79866cf |
11514666313423 has 64 divisors (see below), whose sum is σ = 14911764037632. Its totient is φ = 8641600007040.
The previous prime is 11514666313421. The next prime is 11514666313429. The reversal of 11514666313423 is 32431366641511.
It is not a de Polignac number, because 11514666313423 - 21 = 11514666313421 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11514666313421) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 396728290 + ... + 396757312.
It is an arithmetic number, because the mean of its divisors is an integer number (232996313088).
Almost surely, 211514666313423 is an apocalyptic number.
11514666313423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11514666313423 is a deficient number, since it is larger than the sum of its proper divisors (3397097724209).
11514666313423 is a wasteful number, since it uses less digits than its factorization.
11514666313423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30644.
The product of its digits is 933120, while the sum is 46.
The spelling of 11514666313423 in words is "eleven trillion, five hundred fourteen billion, six hundred sixty-six million, three hundred thirteen thousand, four hundred twenty-three".
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