Base | Representation |
---|---|
bin | 10000110000011001010… |
… | …000110001001011110101 |
3 | 11002002011021110211022202 |
4 | 100300121100301023311 |
5 | 122331210103431433 |
6 | 2240551430434245 |
7 | 146122424350061 |
oct | 20603120611365 |
9 | 4062137424282 |
10 | 1151475061493 |
11 | 404379720629 |
12 | 1671b6802985 |
13 | 84778318043 |
14 | 3da35a88aa1 |
15 | 1ee44ab5ee8 |
hex | 10c194312f5 |
1151475061493 has 2 divisors, whose sum is σ = 1151475061494. Its totient is φ = 1151475061492.
The previous prime is 1151475061463. The next prime is 1151475061543. The reversal of 1151475061493 is 3941605741511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 798231459844 + 353243601649 = 893438^2 + 594343^2 .
It is a cyclic number.
It is not a de Polignac number, because 1151475061493 - 214 = 1151475045109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1151475061423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575737530746 + 575737530747.
It is an arithmetic number, because the mean of its divisors is an integer number (575737530747).
Almost surely, 21151475061493 is an apocalyptic number.
It is an amenable number.
1151475061493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1151475061493 is an equidigital number, since it uses as much as digits as its factorization.
1151475061493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 47.
The spelling of 1151475061493 in words is "one trillion, one hundred fifty-one billion, four hundred seventy-five million, sixty-one thousand, four hundred ninety-three".
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