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1151475061493 is a prime number
BaseRepresentation
bin10000110000011001010…
…000110001001011110101
311002002011021110211022202
4100300121100301023311
5122331210103431433
62240551430434245
7146122424350061
oct20603120611365
94062137424282
101151475061493
11404379720629
121671b6802985
1384778318043
143da35a88aa1
151ee44ab5ee8
hex10c194312f5

1151475061493 has 2 divisors, whose sum is σ = 1151475061494. Its totient is φ = 1151475061492.

The previous prime is 1151475061463. The next prime is 1151475061543. The reversal of 1151475061493 is 3941605741511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 798231459844 + 353243601649 = 893438^2 + 594343^2 .

It is a cyclic number.

It is not a de Polignac number, because 1151475061493 - 214 = 1151475045109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1151475061423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575737530746 + 575737530747.

It is an arithmetic number, because the mean of its divisors is an integer number (575737530747).

Almost surely, 21151475061493 is an apocalyptic number.

It is an amenable number.

1151475061493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151475061493 is an equidigital number, since it uses as much as digits as its factorization.

1151475061493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 453600, while the sum is 47.

The spelling of 1151475061493 in words is "one trillion, one hundred fifty-one billion, four hundred seventy-five million, sixty-one thousand, four hundred ninety-three".