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115153334303551 is a prime number
BaseRepresentation
bin11010001011101100111001…
…100101011111101100111111
3120002201112212212012120222221
4122023230321211133230333
5110043133012040203201
61044524413402350211
733153360654406615
oct3213547145375477
9502645785176887
10115153334303551
113376728919a475
1210ab95a27bb367
134c33bb3647c4b
142061645c236b5
15d4a6085e04a1
hex68bb3995fb3f

115153334303551 has 2 divisors, whose sum is σ = 115153334303552. Its totient is φ = 115153334303550.

The previous prime is 115153334303549. The next prime is 115153334303591. The reversal of 115153334303551 is 155303433351511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115153334303551 - 21 = 115153334303549 is a prime.

It is a super-2 number, since 2×1151533343035512 (a number of 29 digits) contains 22 as substring.

Together with 115153334303549, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 115153334303498 and 115153334303507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115153334303591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576667151775 + 57576667151776.

It is an arithmetic number, because the mean of its divisors is an integer number (57576667151776).

Almost surely, 2115153334303551 is an apocalyptic number.

115153334303551 is a deficient number, since it is larger than the sum of its proper divisors (1).

115153334303551 is an equidigital number, since it uses as much as digits as its factorization.

115153334303551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 607500, while the sum is 43.

The spelling of 115153334303551 in words is "one hundred fifteen trillion, one hundred fifty-three billion, three hundred thirty-four million, three hundred three thousand, five hundred fifty-one".