Base | Representation |
---|---|
bin | 11010001011101100111110… |
… | …010101101110000111101011 |
3 | 120002201120002102021100120022 |
4 | 122023230332111232013223 |
5 | 110043133142444220004 |
6 | 1044524425331551055 |
7 | 33153362643314411 |
oct | 3213547625560753 |
9 | 502646072240508 |
10 | 115153414054379 |
11 | 3376731a210448 |
12 | 10ab960545b48b |
13 | 4c33bc701ba9c |
14 | 20616526632b1 |
15 | d4a6105e52be |
hex | 68bb3e56e1eb |
115153414054379 has 2 divisors, whose sum is σ = 115153414054380. Its totient is φ = 115153414054378.
The previous prime is 115153414054363. The next prime is 115153414054433. The reversal of 115153414054379 is 973450414351511.
It is a weak prime.
It is an emirp because it is prime and its reverse (973450414351511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115153414054379 - 24 = 115153414054363 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115153414054379.
It is not a weakly prime, because it can be changed into another prime (115153414054339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576707027189 + 57576707027190.
It is an arithmetic number, because the mean of its divisors is an integer number (57576707027190).
Almost surely, 2115153414054379 is an apocalyptic number.
115153414054379 is a deficient number, since it is larger than the sum of its proper divisors (1).
115153414054379 is an equidigital number, since it uses as much as digits as its factorization.
115153414054379 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536000, while the sum is 53.
The spelling of 115153414054379 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred fourteen million, fifty-four thousand, three hundred seventy-nine".
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