Base | Representation |
---|---|
bin | 11010001011101100111110… |
… | …010101101110001000100001 |
3 | 120002201120002102021100122022 |
4 | 122023230332111232020201 |
5 | 110043133142444220213 |
6 | 1044524425331551225 |
7 | 33153362643314516 |
oct | 3213547625561041 |
9 | 502646072240568 |
10 | 115153414054433 |
11 | 3376731a210497 |
12 | 10ab960545b515 |
13 | 4c33bc701bb11 |
14 | 206165266330d |
15 | d4a6105e5308 |
hex | 68bb3e56e221 |
115153414054433 has 2 divisors, whose sum is σ = 115153414054434. Its totient is φ = 115153414054432.
The previous prime is 115153414054379. The next prime is 115153414054477. The reversal of 115153414054433 is 334450414351511.
It is an a-pointer prime, because the next prime (115153414054477) can be obtained adding 115153414054433 to its sum of digits (44).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92812742119969 + 22340671934464 = 9633937^2 + 4726592^2 .
It is a cyclic number.
It is not a de Polignac number, because 115153414054433 - 230 = 115152340312609 is a prime.
It is not a weakly prime, because it can be changed into another prime (115153414054033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576707027216 + 57576707027217.
It is an arithmetic number, because the mean of its divisors is an integer number (57576707027217).
Almost surely, 2115153414054433 is an apocalyptic number.
It is an amenable number.
115153414054433 is a deficient number, since it is larger than the sum of its proper divisors (1).
115153414054433 is an equidigital number, since it uses as much as digits as its factorization.
115153414054433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 44.
The spelling of 115153414054433 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred fourteen million, fifty-four thousand, four hundred thirty-three".
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