115153414054401 has 4 divisors (see below), whose sum is σ = 153537885405872. Its totient is φ = 76768942702932.

The previous prime is 115153414054379. The next prime is 115153414054433. The reversal of 115153414054401 is 104450414351511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 115153414054401 - 2¹⁴ = 115153414038017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 115153414054401.

It is not an unprimeable number, because it can be changed into a prime (115153414059401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19192235675731 + ... + 19192235675736.

It is an arithmetic number, because the mean of its divisors is an integer number (38384471351468).

Almost surely, 2^{115153414054401} is an apocalyptic number.

It is an amenable number.

115153414054401 is a deficient number, since it is larger than the sum of its proper divisors (38384471351471).

115153414054401 is an equidigital number, since it uses as much as digits as its factorization.

115153414054401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38384471351470.

The product of its (nonzero) digits is 96000, while the sum is 39.

The spelling of 115153414054401 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred fourteen million, fifty-four thousand, four hundred one".