115155322303001 has 2 divisors, whose sum is σ = 115155322303002. Its totient is φ = 115155322303000.

The previous prime is 115155322302907. The next prime is 115155322303003. The reversal of 115155322303001 is 100303223551511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85036080693001 + 30119241610000 = 9221501^2 + 5488100^2 .

It is an emirp because it is prime and its reverse (100303223551511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115155322303001 - 2¹⁰ = 115155322301977 is a prime.

Together with 115155322303003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115155322303003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57577661151500 + 57577661151501.

It is an arithmetic number, because the mean of its divisors is an integer number (57577661151501).

Almost surely, 2^{115155322303001} is an apocalyptic number.

It is an amenable number.

115155322303001 is a deficient number, since it is larger than the sum of its proper divisors (1).

115155322303001 is an equidigital number, since it uses as much as digits as its factorization.

115155322303001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 32.

Adding to 115155322303001 its reverse (100303223551511), we get a palindrome (215458545854512).

The spelling of 115155322303001 in words is "one hundred fifteen trillion, one hundred fifty-five billion, three hundred twenty-two million, three hundred three thousand, one".