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1151706334241 is a prime number
BaseRepresentation
bin10000110000100111000…
…011000000010000100001
311002002202101122200220002
4100300213003000100201
5122332143310143431
62241030411425345
7146131233213461
oct20604703002041
94062671580802
101151706334241
11404488223231
12167260155255
13847b4201718
143da5868bba1
151ee5a04b3cb
hex10c270c0421

1151706334241 has 2 divisors, whose sum is σ = 1151706334242. Its totient is φ = 1151706334240.

The previous prime is 1151706334217. The next prime is 1151706334243. The reversal of 1151706334241 is 1424336071511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 887371536016 + 264334798225 = 942004^2 + 514135^2 .

It is a cyclic number.

It is not a de Polignac number, because 1151706334241 - 222 = 1151702139937 is a prime.

Together with 1151706334243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1151706334195 and 1151706334204.

It is not a weakly prime, because it can be changed into another prime (1151706334243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575853167120 + 575853167121.

It is an arithmetic number, because the mean of its divisors is an integer number (575853167121).

Almost surely, 21151706334241 is an apocalyptic number.

It is an amenable number.

1151706334241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151706334241 is an equidigital number, since it uses as much as digits as its factorization.

1151706334241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 38.

The spelling of 1151706334241 in words is "one trillion, one hundred fifty-one billion, seven hundred six million, three hundred thirty-four thousand, two hundred forty-one".