115200023 has 2 divisors, whose sum is σ = 115200024. Its totient is φ = 115200022.

The previous prime is 115200017. The next prime is 115200047. The reversal of 115200023 is 320002511.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (320002511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115200023 - 2¹⁰ = 115198999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115199980 and 115200007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115200073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57600011 + 57600012.

It is an arithmetic number, because the mean of its divisors is an integer number (57600012).

Almost surely, 2^115200023 is an apocalyptic number.

115200023 is a deficient number, since it is larger than the sum of its proper divisors (1).

115200023 is an equidigital number, since it uses as much as digits as its factorization.

115200023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 115200023 is about 10733.1273634482. The cubic root of 115200023 is about 486.5761920280.

Adding to 115200023 its reverse (320002511), we get a palindrome (435202534).

The spelling of 115200023 in words is "one hundred fifteen million, two hundred thousand, twenty-three".