1152012554711 has 2 divisors, whose sum is σ = 1152012554712. Its totient is φ = 1152012554710.

The previous prime is 1152012554701. The next prime is 1152012554713. The reversal of 1152012554711 is 1174552102511.

It is a strong prime.

It is an emirp because it is prime and its reverse (1174552102511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1152012554711 - 2¹⁰ = 1152012553687 is a prime.

Together with 1152012554713, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1152012554713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576006277355 + 576006277356.

It is an arithmetic number, because the mean of its divisors is an integer number (576006277356).

Almost surely, 2^{1152012554711} is an apocalyptic number.

1152012554711 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152012554711 is an equidigital number, since it uses as much as digits as its factorization.

1152012554711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14000, while the sum is 35.

The spelling of 1152012554711 in words is "one trillion, one hundred fifty-two billion, twelve million, five hundred fifty-four thousand, seven hundred eleven".