Base | Representation |
---|---|
bin | 110101101001011100… |
… | …0110101110101110101 |
3 | 102000100222210110221221 |
4 | 1223102320311311311 |
5 | 3341421030000103 |
6 | 124531523310341 |
7 | 11215641412654 |
oct | 1532270656565 |
9 | 360328713857 |
10 | 115207265653 |
11 | 4494a552947 |
12 | 1a3b281b3b1 |
13 | ab30287b9c |
14 | 580c9d919b |
15 | 2ee43411bd |
hex | 1ad2e35d75 |
115207265653 has 2 divisors, whose sum is σ = 115207265654. Its totient is φ = 115207265652.
The previous prime is 115207265647. The next prime is 115207265659. The reversal of 115207265653 is 356562702511.
It is a balanced prime because it is at equal distance from previous prime (115207265647) and next prime (115207265659).
It can be written as a sum of positive squares in only one way, i.e., 115152992964 + 54272689 = 339342^2 + 7367^2 .
It is a cyclic number.
It is not a de Polignac number, because 115207265653 - 213 = 115207257461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115207265659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57603632826 + 57603632827.
It is an arithmetic number, because the mean of its divisors is an integer number (57603632827).
Almost surely, 2115207265653 is an apocalyptic number.
It is an amenable number.
115207265653 is a deficient number, since it is larger than the sum of its proper divisors (1).
115207265653 is an equidigital number, since it uses as much as digits as its factorization.
115207265653 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 115207265653 in words is "one hundred fifteen billion, two hundred seven million, two hundred sixty-five thousand, six hundred fifty-three".
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