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115225353454241 is a prime number
BaseRepresentation
bin11010001100101111111110…
…010000110000001010100001
3120002222102202222221111220102
4122030233332100300022201
5110100323010441013431
61045021444022552145
733161520450162152
oct3214577620601241
9502872688844812
10115225353454241
1133794886119318
1210b0b541898655
134c3a9201b3604
142064d18a7b929
15d4c4210e7dcb
hex68cbfe4302a1

115225353454241 has 2 divisors, whose sum is σ = 115225353454242. Its totient is φ = 115225353454240.

The previous prime is 115225353454231. The next prime is 115225353454243. The reversal of 115225353454241 is 142454353522511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94238876244241 + 20986477210000 = 9707671^2 + 4581100^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115225353454241 is a prime.

Together with 115225353454243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115225353454243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57612676727120 + 57612676727121.

It is an arithmetic number, because the mean of its divisors is an integer number (57612676727121).

Almost surely, 2115225353454241 is an apocalyptic number.

It is an amenable number.

115225353454241 is a deficient number, since it is larger than the sum of its proper divisors (1).

115225353454241 is an equidigital number, since it uses as much as digits as its factorization.

115225353454241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880000, while the sum is 47.

The spelling of 115225353454241 in words is "one hundred fifteen trillion, two hundred twenty-five billion, three hundred fifty-three million, four hundred fifty-four thousand, two hundred forty-one".