Base | Representation |
---|---|
bin | 1010011110101110001010… |
… | …0011000101111100101101 |
3 | 1111210120121221011100120202 |
4 | 2213223202203011330231 |
5 | 3002242401200404333 |
6 | 40301314300323245 |
7 | 2266334165420234 |
oct | 247534243057455 |
9 | 44716557140522 |
10 | 11522903138093 |
11 | 3742921469006 |
12 | 1361270b43525 |
13 | 6577b3548939 |
14 | 2bb9d6471b1b |
15 | 14eb0cd675e8 |
hex | a7ae28c5f2d |
11522903138093 has 2 divisors, whose sum is σ = 11522903138094. Its totient is φ = 11522903138092.
The previous prime is 11522903138083. The next prime is 11522903138119. The reversal of 11522903138093 is 39083130922511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11353543728004 + 169359410089 = 3369502^2 + 411533^2 .
It is a cyclic number.
It is not a de Polignac number, because 11522903138093 - 210 = 11522903137069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11522903138083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5761451569046 + 5761451569047.
It is an arithmetic number, because the mean of its divisors is an integer number (5761451569047).
Almost surely, 211522903138093 is an apocalyptic number.
It is an amenable number.
11522903138093 is a deficient number, since it is larger than the sum of its proper divisors (1).
11522903138093 is an equidigital number, since it uses as much as digits as its factorization.
11522903138093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 349920, while the sum is 47.
The spelling of 11522903138093 in words is "eleven trillion, five hundred twenty-two billion, nine hundred three million, one hundred thirty-eight thousand, ninety-three".
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