Base | Representation |
---|---|
bin | 1010011110110011000100… |
… | …0011011010001010001010 |
3 | 1111210201000201111200012210 |
4 | 2213230301003122022022 |
5 | 3002303100334413310 |
6 | 40302053110245550 |
7 | 2266411630505151 |
oct | 247546103321212 |
9 | 44721021450183 |
10 | 11524220232330 |
11 | 3743437981443 |
12 | 136157a0568b6 |
13 | 65796338a540 |
14 | 2bbabd362598 |
15 | 14eb887d2820 |
hex | a7b310da28a |
11524220232330 has 64 divisors (see below), whose sum is σ = 29850288386688. Its totient is φ = 2830577660160.
The previous prime is 11524220232307. The next prime is 11524220232341. The reversal of 11524220232330 is 3323202242511.
It is a super-3 number, since 3×115242202323303 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31869324 + ... + 32228903.
It is an arithmetic number, because the mean of its divisors is an integer number (466410756042).
Almost surely, 211524220232330 is an apocalyptic number.
11524220232330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11524220232330 is an abundant number, since it is smaller than the sum of its proper divisors (18326068154358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11524220232330 is a wasteful number, since it uses less digits than its factorization.
11524220232330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64098711.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 11524220232330 its reverse (3323202242511), we get a palindrome (14847422474841).
The spelling of 11524220232330 in words is "eleven trillion, five hundred twenty-four billion, two hundred twenty million, two hundred thirty-two thousand, three hundred thirty".
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