Base | Representation |
---|---|
bin | 110101101100011000… |
… | …1011110000011001101 |
3 | 102000121212120112012201 |
4 | 1223120301132003031 |
5 | 3342121313341433 |
6 | 124545411401501 |
7 | 11221250540662 |
oct | 1533061360315 |
9 | 360555515181 |
10 | 115305996493 |
11 | 449a0257886 |
12 | 1a41b8b3291 |
13 | ab47875abc |
14 | 581bb79a69 |
15 | 2eecd44a7d |
hex | 1ad8c5e0cd |
115305996493 has 2 divisors, whose sum is σ = 115305996494. Its totient is φ = 115305996492.
The previous prime is 115305996473. The next prime is 115305996497. The reversal of 115305996493 is 394699503511.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114830843689 + 475152804 = 338867^2 + 21798^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115305996493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115305996497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57652998246 + 57652998247.
It is an arithmetic number, because the mean of its divisors is an integer number (57652998247).
Almost surely, 2115305996493 is an apocalyptic number.
It is an amenable number.
115305996493 is a deficient number, since it is larger than the sum of its proper divisors (1).
115305996493 is an equidigital number, since it uses as much as digits as its factorization.
115305996493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3936600, while the sum is 55.
The spelling of 115305996493 in words is "one hundred fifteen billion, three hundred five million, nine hundred ninety-six thousand, four hundred ninety-three".
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