Base | Representation |
---|---|
bin | 10101011110100110… |
… | …10100110100011000 |
3 | 1002202121122011200101 |
4 | 22233103110310120 |
5 | 142103414412100 |
6 | 5144113345144 |
7 | 555514665604 |
oct | 125723246430 |
9 | 32677564611 |
10 | 11531013400 |
11 | 4987a58045 |
12 | 22998681b4 |
13 | 1119c4aa6a |
14 | 7b561a504 |
15 | 4774d186a |
hex | 2af4d4d18 |
11531013400 has 48 divisors (see below), whose sum is σ = 26837668440. Its totient is φ = 4607577600.
The previous prime is 11531013391. The next prime is 11531013413. The reversal of 11531013400 is 431013511.
11531013400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 164512 + ... + 223888.
Almost surely, 211531013400 is an apocalyptic number.
11531013400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11531013400 is an abundant number, since it is smaller than the sum of its proper divisors (15306655040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11531013400 is a wasteful number, since it uses less digits than its factorization.
11531013400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60364 (or 60355 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 11531013400 its reverse (431013511), we get a palindrome (11962026911).
The spelling of 11531013400 in words is "eleven billion, five hundred thirty-one million, thirteen thousand, four hundred".
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