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11531054453 is a prime number
BaseRepresentation
bin10101011110100110…
…11110110101110101
31002202121201020222212
422233103132311311
5142103422220303
65144114303205
7555515226362
oct125723366565
932677636885
1011531054453
114987a85976
122299887b05
131119c63659
147b562b469
154774ddad8
hex2af4ded75

11531054453 has 2 divisors, whose sum is σ = 11531054454. Its totient is φ = 11531054452.

The previous prime is 11531054441. The next prime is 11531054467. The reversal of 11531054453 is 35445013511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7644529489 + 3886524964 = 87433^2 + 62342^2 .

It is a cyclic number.

It is not a de Polignac number, because 11531054453 - 224 = 11514277237 is a prime.

It is a super-2 number, since 2×115310544532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11531054473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765527226 + 5765527227.

It is an arithmetic number, because the mean of its divisors is an integer number (5765527227).

Almost surely, 211531054453 is an apocalyptic number.

It is an amenable number.

11531054453 is a deficient number, since it is larger than the sum of its proper divisors (1).

11531054453 is an equidigital number, since it uses as much as digits as its factorization.

11531054453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 11531054453 its reverse (35445013511), we get a palindrome (46976067964).

The spelling of 11531054453 in words is "eleven billion, five hundred thirty-one million, fifty-four thousand, four hundred fifty-three".