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1153135141 is a prime number
BaseRepresentation
bin100010010111011…
…0111001000100101
32222100211100000221
41010232313020211
54330200311031
6310231404341
740401326014
oct10456671045
92870740027
101153135141
11541a07554
122822236b1
13154b960b2
14ad210a7b
156b37ea11
hex44bb7225

1153135141 has 2 divisors, whose sum is σ = 1153135142. Its totient is φ = 1153135140.

The previous prime is 1153135121. The next prime is 1153135157. The reversal of 1153135141 is 1415313511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1093691041 + 59444100 = 33071^2 + 7710^2 .

It is a cyclic number.

It is not a de Polignac number, because 1153135141 - 29 = 1153134629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1153135121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576567570 + 576567571.

It is an arithmetic number, because the mean of its divisors is an integer number (576567571).

Almost surely, 21153135141 is an apocalyptic number.

It is an amenable number.

1153135141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153135141 is an equidigital number, since it uses as much as digits as its factorization.

1153135141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 900, while the sum is 25.

The square root of 1153135141 is about 33957.8435858345. The cubic root of 1153135141 is about 1048.6407630559.

Adding to 1153135141 its reverse (1415313511), we get a palindrome (2568448652).

The spelling of 1153135141 in words is "one billion, one hundred fifty-three million, one hundred thirty-five thousand, one hundred forty-one".