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11532241031 is a prime number
BaseRepresentation
bin10101011110110000…
…00000100010000111
31002202200221112200012
422233120000202013
5142104223203111
65144155540435
7555531300653
oct125730004207
932680845605
1011532241031
114988716413
12229a15a71b
13111a28a77c
147b5859a63
1547767548b
hex2af600887

11532241031 has 2 divisors, whose sum is σ = 11532241032. Its totient is φ = 11532241030.

The previous prime is 11532241027. The next prime is 11532241033. The reversal of 11532241031 is 13014223511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11532241031 - 22 = 11532241027 is a prime.

It is a super-2 number, since 2×115322410312 (a number of 21 digits) contains 22 as substring.

Together with 11532241033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11532240988 and 11532241006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11532241033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766120515 + 5766120516.

It is an arithmetic number, because the mean of its divisors is an integer number (5766120516).

Almost surely, 211532241031 is an apocalyptic number.

11532241031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11532241031 is an equidigital number, since it uses as much as digits as its factorization.

11532241031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 11532241031 its reverse (13014223511), we get a palindrome (24546464542).

The spelling of 11532241031 in words is "eleven billion, five hundred thirty-two million, two hundred forty-one thousand, thirty-one".