Base | Representation |
---|---|
bin | 10101011110110000… |
… | …00000100010000111 |
3 | 1002202200221112200012 |
4 | 22233120000202013 |
5 | 142104223203111 |
6 | 5144155540435 |
7 | 555531300653 |
oct | 125730004207 |
9 | 32680845605 |
10 | 11532241031 |
11 | 4988716413 |
12 | 229a15a71b |
13 | 111a28a77c |
14 | 7b5859a63 |
15 | 47767548b |
hex | 2af600887 |
11532241031 has 2 divisors, whose sum is σ = 11532241032. Its totient is φ = 11532241030.
The previous prime is 11532241027. The next prime is 11532241033. The reversal of 11532241031 is 13014223511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11532241031 - 22 = 11532241027 is a prime.
It is a super-2 number, since 2×115322410312 (a number of 21 digits) contains 22 as substring.
Together with 11532241033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11532240988 and 11532241006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11532241033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766120515 + 5766120516.
It is an arithmetic number, because the mean of its divisors is an integer number (5766120516).
Almost surely, 211532241031 is an apocalyptic number.
11532241031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11532241031 is an equidigital number, since it uses as much as digits as its factorization.
11532241031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 11532241031 its reverse (13014223511), we get a palindrome (24546464542).
The spelling of 11532241031 in words is "eleven billion, five hundred thirty-two million, two hundred forty-one thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •