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11532241213 is a prime number
BaseRepresentation
bin10101011110110000…
…00000100100111101
31002202200221112220221
422233120000210331
5142104223204323
65144155541341
7555531301333
oct125730004475
932680845827
1011532241213
114988716569
12229a15a851
13111a28a88c
147b5859b53
1547767555d
hex2af60093d

11532241213 has 2 divisors, whose sum is σ = 11532241214. Its totient is φ = 11532241212.

The previous prime is 11532241169. The next prime is 11532241229. The reversal of 11532241213 is 31214223511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11228157369 + 304083844 = 105963^2 + 17438^2 .

It is a cyclic number.

It is not a de Polignac number, because 11532241213 - 217 = 11532110141 is a prime.

It is a super-2 number, since 2×115322412132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11532241313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766120606 + 5766120607.

It is an arithmetic number, because the mean of its divisors is an integer number (5766120607).

Almost surely, 211532241213 is an apocalyptic number.

It is an amenable number.

11532241213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11532241213 is an equidigital number, since it uses as much as digits as its factorization.

11532241213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 25.

Adding to 11532241213 its reverse (31214223511), we get a palindrome (42746464724).

The spelling of 11532241213 in words is "eleven billion, five hundred thirty-two million, two hundred forty-one thousand, two hundred thirteen".