Base | Representation |
---|---|
bin | 1010011111010100001001… |
… | …0101100010110001000101 |
3 | 1111211112221120121101112021 |
4 | 2213311002111202301011 |
5 | 3002424242113232240 |
6 | 40310122201323141 |
7 | 2300144654433532 |
oct | 247650225426105 |
9 | 44745846541467 |
10 | 11533100133445 |
11 | 37471843a35a0 |
12 | 1363237a964b1 |
13 | 658749caa8b7 |
14 | 2bc2c2833d89 |
15 | 15000818954a |
hex | a7d42562c45 |
11533100133445 has 32 divisors (see below), whose sum is σ = 15246633600000. Its totient is φ = 8305169863680.
The previous prime is 11533100133437. The next prime is 11533100133449. The reversal of 11533100133445 is 54433100133511.
It is not a de Polignac number, because 11533100133445 - 23 = 11533100133437 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11533100133445.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11533100133449) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8280556 + ... + 9572554.
It is an arithmetic number, because the mean of its divisors is an integer number (476457300000).
Almost surely, 211533100133445 is an apocalyptic number.
It is an amenable number.
11533100133445 is a deficient number, since it is larger than the sum of its proper divisors (3713533466555).
11533100133445 is a wasteful number, since it uses less digits than its factorization.
11533100133445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1293613.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 11533100133445 its reverse (54433100133511), we get a palindrome (65966200266956).
The spelling of 11533100133445 in words is "eleven trillion, five hundred thirty-three billion, one hundred million, one hundred thirty-three thousand, four hundred forty-five".
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