Base | Representation |
---|---|
bin | 11010001110011011111111… |
… | …010100110110010111111111 |
3 | 120010101112010222110222000002 |
4 | 122032123333110312113333 |
5 | 110104223023332004323 |
6 | 1045151024503024515 |
7 | 33203064546510203 |
oct | 3216337724662777 |
9 | 503345128428002 |
10 | 115341335422463 |
11 | 33829a929a3717 |
12 | 10b29b0ba3b13b |
13 | 4c48844b04987 |
14 | 206a79c4d8b03 |
15 | d5045d465828 |
hex | 68e6ff5365ff |
115341335422463 has 2 divisors, whose sum is σ = 115341335422464. Its totient is φ = 115341335422462.
The previous prime is 115341335422447. The next prime is 115341335422471. The reversal of 115341335422463 is 364224533143511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115341335422463 - 24 = 115341335422447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115341335427463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57670667711231 + 57670667711232.
It is an arithmetic number, because the mean of its divisors is an integer number (57670667711232).
Almost surely, 2115341335422463 is an apocalyptic number.
115341335422463 is a deficient number, since it is larger than the sum of its proper divisors (1).
115341335422463 is an equidigital number, since it uses as much as digits as its factorization.
115341335422463 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3110400, while the sum is 47.
Adding to 115341335422463 its reverse (364224533143511), we get a palindrome (479565868565974).
The spelling of 115341335422463 in words is "one hundred fifteen trillion, three hundred forty-one billion, three hundred thirty-five million, four hundred twenty-two thousand, four hundred sixty-three".
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