Base | Representation |
---|---|
bin | 11010001110011101110101… |
… | …110100001010101001101111 |
3 | 120010101201021112002210222002 |
4 | 122032131311310022221233 |
5 | 110104241111233442341 |
6 | 1045151554035042515 |
7 | 33203165035533236 |
oct | 3216356564125157 |
9 | 503351245083862 |
10 | 115343323343471 |
11 | 3382a913040143 |
12 | 10b2a38574043b |
13 | 4c48aa09100b2 |
14 | 206a90a52bb1d |
15 | d50527c3e29b |
hex | 68e775d0aa6f |
115343323343471 has 2 divisors, whose sum is σ = 115343323343472. Its totient is φ = 115343323343470.
The previous prime is 115343323343387. The next prime is 115343323343561. The reversal of 115343323343471 is 174343323343511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115343323343471 is a prime.
It is a super-3 number, since 3×1153433233434713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115343323333471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57671661671735 + 57671661671736.
It is an arithmetic number, because the mean of its divisors is an integer number (57671661671736).
Almost surely, 2115343323343471 is an apocalyptic number.
115343323343471 is a deficient number, since it is larger than the sum of its proper divisors (1).
115343323343471 is an equidigital number, since it uses as much as digits as its factorization.
115343323343471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3265920, while the sum is 47.
Adding to 115343323343471 its reverse (174343323343511), we get a palindrome (289686646686982).
The spelling of 115343323343471 in words is "one hundred fifteen trillion, three hundred forty-three billion, three hundred twenty-three million, three hundred forty-three thousand, four hundred seventy-one".
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