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115343323343471 is a prime number
BaseRepresentation
bin11010001110011101110101…
…110100001010101001101111
3120010101201021112002210222002
4122032131311310022221233
5110104241111233442341
61045151554035042515
733203165035533236
oct3216356564125157
9503351245083862
10115343323343471
113382a913040143
1210b2a38574043b
134c48aa09100b2
14206a90a52bb1d
15d50527c3e29b
hex68e775d0aa6f

115343323343471 has 2 divisors, whose sum is σ = 115343323343472. Its totient is φ = 115343323343470.

The previous prime is 115343323343387. The next prime is 115343323343561. The reversal of 115343323343471 is 174343323343511.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115343323343471 is a prime.

It is a super-3 number, since 3×1153433233434713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115343323333471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57671661671735 + 57671661671736.

It is an arithmetic number, because the mean of its divisors is an integer number (57671661671736).

Almost surely, 2115343323343471 is an apocalyptic number.

115343323343471 is a deficient number, since it is larger than the sum of its proper divisors (1).

115343323343471 is an equidigital number, since it uses as much as digits as its factorization.

115343323343471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3265920, while the sum is 47.

Adding to 115343323343471 its reverse (174343323343511), we get a palindrome (289686646686982).

The spelling of 115343323343471 in words is "one hundred fifteen trillion, three hundred forty-three billion, three hundred twenty-three million, three hundred forty-three thousand, four hundred seventy-one".