115347131401 has 2 divisors, whose sum is σ = 115347131402. Its totient is φ = 115347131400.

The previous prime is 115347131399. The next prime is 115347131467. The reversal of 115347131401 is 104131743511.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104057856400 + 11289275001 = 322580^2 + 106251^2 .

It is an emirp because it is prime and its reverse (104131743511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115347131401 - 2¹ = 115347131399 is a prime.

Together with 115347131399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (115347111401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57673565700 + 57673565701.

It is an arithmetic number, because the mean of its divisors is an integer number (57673565701).

Almost surely, 2^115347131401 is an apocalyptic number.

It is an amenable number.

115347131401 is a deficient number, since it is larger than the sum of its proper divisors (1).

115347131401 is an equidigital number, since it uses as much as digits as its factorization.

115347131401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 115347131401 its reverse (104131743511), we get a palindrome (219478874912).

The spelling of 115347131401 in words is "one hundred fifteen billion, three hundred forty-seven million, one hundred thirty-one thousand, four hundred one".