11535443141 has 2 divisors, whose sum is σ = 11535443142. Its totient is φ = 11535443140.

The previous prime is 11535443083. The next prime is 11535443159. The reversal of 11535443141 is 14134453511.

11535443141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7169008900 + 4366434241 = 84670^2 + 66079^2 .

It is a cyclic number.

It is not a de Polignac number, because 11535443141 - 2¹⁸ = 11535180997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11535443098 and 11535443107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11535443641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5767721570 + 5767721571.

It is an arithmetic number, because the mean of its divisors is an integer number (5767721571).

Almost surely, 2^11535443141 is an apocalyptic number.

It is an amenable number.

11535443141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11535443141 is an equidigital number, since it uses as much as digits as its factorization.

11535443141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 32.

Adding to 11535443141 its reverse (14134453511), we get a palindrome (25669896652).

The spelling of 11535443141 in words is "eleven billion, five hundred thirty-five million, four hundred forty-three thousand, one hundred forty-one".