Base | Representation |
---|---|
bin | 11010001110101001001110… |
… | …101010111011101000111111 |
3 | 120010102212211201120012021102 |
4 | 122032221032222323220333 |
5 | 110104441132141410101 |
6 | 1045201335255123315 |
7 | 33204110050340555 |
oct | 3216511652735077 |
9 | 503385751505242 |
10 | 115355551513151 |
11 | 33835018574aa4 |
12 | 10b3081897353b |
13 | 4c49c9c112a61 |
14 | 206b34a581bd5 |
15 | d509e153086b |
hex | 68ea4eabba3f |
115355551513151 has 2 divisors, whose sum is σ = 115355551513152. Its totient is φ = 115355551513150.
The previous prime is 115355551513129. The next prime is 115355551513183. The reversal of 115355551513151 is 151315155553511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115355551513151 - 226 = 115355484404287 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 115355551513096 and 115355551513105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115355551510151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57677775756575 + 57677775756576.
It is an arithmetic number, because the mean of its divisors is an integer number (57677775756576).
Almost surely, 2115355551513151 is an apocalyptic number.
115355551513151 is a deficient number, since it is larger than the sum of its proper divisors (1).
115355551513151 is an equidigital number, since it uses as much as digits as its factorization.
115355551513151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 703125, while the sum is 47.
The spelling of 115355551513151 in words is "one hundred fifteen trillion, three hundred fifty-five billion, five hundred fifty-one million, five hundred thirteen thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •