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115386573473 is a prime number
BaseRepresentation
bin110101101110110010…
…0110110001010100001
3102000211111012021001022
41223131210312022201
53342302430322343
6125001410415225
711223246456203
oct1533544661241
9360744167038
10115386573473
1144a31792526
121a442891515
13ab5b4789a2
145828752773
153004e5e568
hex1add9362a1

115386573473 has 2 divisors, whose sum is σ = 115386573474. Its totient is φ = 115386573472.

The previous prime is 115386573457. The next prime is 115386573481. The reversal of 115386573473 is 374375683511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64451500129 + 50935073344 = 253873^2 + 225688^2 .

It is a cyclic number.

It is not a de Polignac number, because 115386573473 - 24 = 115386573457 is a prime.

It is a super-2 number, since 2×1153865734732 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115386573173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57693286736 + 57693286737.

It is an arithmetic number, because the mean of its divisors is an integer number (57693286737).

Almost surely, 2115386573473 is an apocalyptic number.

It is an amenable number.

115386573473 is a deficient number, since it is larger than the sum of its proper divisors (1).

115386573473 is an equidigital number, since it uses as much as digits as its factorization.

115386573473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6350400, while the sum is 53.

The spelling of 115386573473 in words is "one hundred fifteen billion, three hundred eighty-six million, five hundred seventy-three thousand, four hundred seventy-three".