Base | Representation |
---|---|
bin | 10101011111101111… |
… | …11010010110101010 |
3 | 1002210021200102222000 |
4 | 22233313322112222 |
5 | 142113343314310 |
6 | 5145055111430 |
7 | 555662342523 |
oct | 125767722652 |
9 | 32707612860 |
10 | 11540604330 |
11 | 4992408932 |
12 | 22a0b12576 |
13 | 111bc28378 |
14 | 7b69d584a |
15 | 4782784c0 |
hex | 2afdfa5aa |
11540604330 has 32 divisors (see below), whose sum is σ = 30774945600. Its totient is φ = 3077494416.
The previous prime is 11540604319. The next prime is 11540604367. The reversal of 11540604330 is 3340604511.
11540604330 is a `hidden beast` number, since 1 + 1 + 54 + 0 + 604 + 3 + 3 + 0 = 666.
It is a super-2 number, since 2×115406043302 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 11540604294 and 11540604303.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21371220 + ... + 21371759.
It is an arithmetic number, because the mean of its divisors is an integer number (961717050).
Almost surely, 211540604330 is an apocalyptic number.
11540604330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11540604330 is an abundant number, since it is smaller than the sum of its proper divisors (19234341270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11540604330 is a wasteful number, since it uses less digits than its factorization.
11540604330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42742995 (or 42742989 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
The spelling of 11540604330 in words is "eleven billion, five hundred forty million, six hundred four thousand, three hundred thirty".
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