115413437 has 2 divisors, whose sum is σ = 115413438. Its totient is φ = 115413436.

The previous prime is 115413373. The next prime is 115413439. The reversal of 115413437 is 734314511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73085401 + 42328036 = 8549^2 + 6506^2 .

It is a cyclic number.

It is not a de Polignac number, because 115413437 - 2⁶ = 115413373 is a prime.

It is a super-3 number, since 3×115413437³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 115413439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115413439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57706718 + 57706719.

It is an arithmetic number, because the mean of its divisors is an integer number (57706719).

Almost surely, 2^115413437 is an apocalyptic number.

It is an amenable number.

115413437 is a deficient number, since it is larger than the sum of its proper divisors (1).

115413437 is an equidigital number, since it uses as much as digits as its factorization.

115413437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5040, while the sum is 29.

The square root of 115413437 is about 10743.0646000106. The cubic root of 115413437 is about 486.8764758599.

Adding to 115413437 its reverse (734314511), we get a palindrome (849727948).

The spelling of 115413437 in words is "one hundred fifteen million, four hundred thirteen thousand, four hundred thirty-seven".