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115428431 is a prime number
BaseRepresentation
bin1101110000101…
…00110001001111
322001012101001002
412320110301033
5214022202211
615242010515
72601061016
oct670246117
9261171032
10115428431
115a17a0a8
12327a6a3b
131abb6161
1411489a7d
15a20103b
hex6e14c4f

115428431 has 2 divisors, whose sum is σ = 115428432. Its totient is φ = 115428430.

The previous prime is 115428413. The next prime is 115428449. The reversal of 115428431 is 134824511.

Together with previous prime (115428413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (115428413) and next prime (115428449).

It is a cyclic number.

It is not a de Polignac number, because 115428431 - 214 = 115412047 is a prime.

It is a super-2 number, since 2×1154284312 = 26647445366243522, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115428394 and 115428403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115428491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57714215 + 57714216.

It is an arithmetic number, because the mean of its divisors is an integer number (57714216).

Almost surely, 2115428431 is an apocalyptic number.

115428431 is a deficient number, since it is larger than the sum of its proper divisors (1).

115428431 is an equidigital number, since it uses as much as digits as its factorization.

115428431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3840, while the sum is 29.

The square root of 115428431 is about 10743.7624229131. The cubic root of 115428431 is about 486.8975592217.

The spelling of 115428431 in words is "one hundred fifteen million, four hundred twenty-eight thousand, four hundred thirty-one".