Base | Representation |
---|---|
bin | 11010010000000010001010… |
… | …010111011011100001011011 |
3 | 120010210000022122100111121102 |
4 | 122100002022113123201123 |
5 | 110113022213313024311 |
6 | 1045313250542302015 |
7 | 33214030311634043 |
oct | 3220021227334133 |
9 | 503700278314542 |
10 | 115451042314331 |
11 | 3387156a6472a9 |
12 | 10b4722858790b |
13 | 4c55ca96779c9 |
14 | 2071c087c0723 |
15 | d5322e96143b |
hex | 69008a5db85b |
115451042314331 has 2 divisors, whose sum is σ = 115451042314332. Its totient is φ = 115451042314330.
The previous prime is 115451042314319. The next prime is 115451042314339. The reversal of 115451042314331 is 133413240154511.
It is a strong prime.
It is an emirp because it is prime and its reverse (133413240154511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115451042314331 - 218 = 115451042052187 is a prime.
It is a super-2 number, since 2×1154510423143312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115451042314339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57725521157165 + 57725521157166.
It is an arithmetic number, because the mean of its divisors is an integer number (57725521157166).
Almost surely, 2115451042314331 is an apocalyptic number.
115451042314331 is a deficient number, since it is larger than the sum of its proper divisors (1).
115451042314331 is an equidigital number, since it uses as much as digits as its factorization.
115451042314331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 115451042314331 its reverse (133413240154511), we get a palindrome (248864282468842).
The spelling of 115451042314331 in words is "one hundred fifteen trillion, four hundred fifty-one billion, forty-two million, three hundred fourteen thousand, three hundred thirty-one".
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