Base | Representation |
---|---|
bin | 11110010101011010110000… |
… | …110010011010100110001111 |
3 | 122111101011220002112110201202 |
4 | 132111122300302122212033 |
5 | 114441320303434421021 |
6 | 1151425110232100115 |
7 | 40046534314262252 |
oct | 3625326062324617 |
9 | 574334802473652 |
10 | 133413240154511 |
11 | 39567267a9a359 |
12 | 12b6846823463b |
13 | 5959a7879b375 |
14 | 24d3341859099 |
15 | 10655b7c74a0b |
hex | 7956b0c9a98f |
133413240154511 has 2 divisors, whose sum is σ = 133413240154512. Its totient is φ = 133413240154510.
The previous prime is 133413240154507. The next prime is 133413240154531. The reversal of 133413240154511 is 115451042314331.
It is a weak prime.
It is an emirp because it is prime and its reverse (115451042314331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133413240154511 - 22 = 133413240154507 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133413240154531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706620077255 + 66706620077256.
It is an arithmetic number, because the mean of its divisors is an integer number (66706620077256).
Almost surely, 2133413240154511 is an apocalyptic number.
133413240154511 is a deficient number, since it is larger than the sum of its proper divisors (1).
133413240154511 is an equidigital number, since it uses as much as digits as its factorization.
133413240154511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 133413240154511 its reverse (115451042314331), we get a palindrome (248864282468842).
The spelling of 133413240154511 in words is "one hundred thirty-three trillion, four hundred thirteen billion, two hundred forty million, one hundred fifty-four thousand, five hundred eleven".
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