Base | Representation |
---|---|
bin | 10101100000010010… |
… | …01000110111100111 |
3 | 1002210121011212121121 |
4 | 22300021020313213 |
5 | 142121022321411 |
6 | 5145335554411 |
7 | 556045621441 |
oct | 126011106747 |
9 | 32717155547 |
10 | 11545120231 |
11 | 4994a12787 |
12 | 22a252ba07 |
13 | 111cb499b8 |
14 | 7b744d491 |
15 | 47886b571 |
hex | 2b0248de7 |
11545120231 has 2 divisors, whose sum is σ = 11545120232. Its totient is φ = 11545120230.
The previous prime is 11545120159. The next prime is 11545120261. The reversal of 11545120231 is 13202154511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11545120231 - 229 = 11008249319 is a prime.
It is a super-2 number, since 2×115451202312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11545120196 and 11545120205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11545120261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772560115 + 5772560116.
It is an arithmetic number, because the mean of its divisors is an integer number (5772560116).
Almost surely, 211545120231 is an apocalyptic number.
11545120231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11545120231 is an equidigital number, since it uses as much as digits as its factorization.
11545120231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 11545120231 its reverse (13202154511), we get a palindrome (24747274742).
The spelling of 11545120231 in words is "eleven billion, five hundred forty-five million, one hundred twenty thousand, two hundred thirty-one".
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